Nevada · United States
Summerlin South population
24,085people · latest figure
Summerlin South has a population of 24,085, making it the 1870th largest place we list in United States. It is in Nevada.
Summerlin South holds under a tenth of one per cent of United States's 349,035,494 people. New York City, the largest place we list there, is 366 times its size.
24,085
population
#1,870
Summerlin South is in Nevada, which has 79 recorded places.
Nearby in size
| Place | Region | Population |
|---|---|---|
| Zion | Illinois | 24,117 |
| Trotwood | Ohio | 24,096 |
| North Haven | Connecticut | 24,093 |
| Mahwah | New Jersey | 24,062 |
| Peekskill | New York | 24,043 |
| Keystone | Florida | 24,039 |
All places in United States → · Nevada →
Figures are the latest available in GeoNames (CC BY 4.0), which draws on national censuses of varying dates — treat them as recent, not same-year. Country totals are UN World Population Prospects 2024 (medium variant) where the UN lists the country separately; the handful it reports under a parent state keep a GeoNames figure and are marked as such. Sources & method.