Alaska · United States
Selawik population
859people · latest figure
Selawik has a population of 859, making it the 8621st largest place we list in United States. It is in Alaska.
Selawik holds under a tenth of one per cent of United States's 349,035,494 people. New York City, the largest place we list there, is 10249 times its size. Twenty years earlier the World Gazetteer recorded 800, a rise of 7%.
The 2005 figure comes from the World Gazetteer archive restored on this site. The two sources may draw the settlement's boundary differently, so treat the change as indicative rather than exact. Why figures differ.
Selawik is in Alaska, which has 121 recorded places.
Nearby in size
| Place | Region | Population |
|---|---|---|
| Naalehu | Hawaii | 866 |
| Lumberport | West Virginia | 863 |
| Henefer | Utah | 862 |
| Dagsboro | Delaware | 859 |
| Elsinore | Utah | 857 |
| Tatum | New Mexico | 857 |
All places in United States → · Alaska →
Figures are the latest available in GeoNames (CC BY 4.0), which draws on national censuses of varying dates — treat them as recent, not same-year. Country totals are UN World Population Prospects 2024 (medium variant) where the UN lists the country separately; the handful it reports under a parent state keep a GeoNames figure and are marked as such. Sources & method.