Alaska · United States
Seward population
2,790people · latest figure
Seward has a population of 2,790, making it the 6673rd largest place we list in United States. It is in Alaska.
Seward holds under a tenth of one per cent of United States's 349,035,494 people. New York City, the largest place we list there, is 3156 times its size. Twenty years earlier the World Gazetteer recorded 6,950, a fall of 60%.
The 2005 figure comes from the World Gazetteer archive restored on this site. The two sources may draw the settlement's boundary differently, so treat the change as indicative rather than exact. Why figures differ.
Seward is in Alaska, which has 121 recorded places.
Nearby in size
| Place | Region | Population |
|---|---|---|
| Many | Louisiana | 2,790 |
| West Hammond | New Mexico | 2,790 |
| Ruleville | Mississippi | 2,790 |
| Brusly | Louisiana | 2,785 |
| Springdale | South Carolina | 2,783 |
| Blythewood | South Carolina | 2,782 |
All places in United States → · Alaska →
Figures are the latest available in GeoNames (CC BY 4.0), which draws on national censuses of varying dates — treat them as recent, not same-year. Country totals are UN World Population Prospects 2024 (medium variant) where the UN lists the country separately; the handful it reports under a parent state keep a GeoNames figure and are marked as such. Sources & method.