Nevada · United States
Sandy Valley population
2,051people · latest figure
Sandy Valley has a population of 2,051, making it the 7289th largest place we list in United States. It is in Nevada.
Sandy Valley holds under a tenth of one per cent of United States's 349,035,494 people. New York City, the largest place we list there, is 4293 times its size. Twenty years earlier the World Gazetteer recorded 2,166, a fall of 5%.
The 2005 figure comes from the World Gazetteer archive restored on this site. The two sources may draw the settlement's boundary differently, so treat the change as indicative rather than exact. Why figures differ.
Sandy Valley is in Nevada, which has 79 recorded places.
Nearby in size
| Place | Region | Population |
|---|---|---|
| La Salle | Colorado | 2,052 |
| Kershaw | South Carolina | 2,052 |
| Lame Deer | Montana | 2,052 |
| Colfax | Iowa | 2,051 |
| Augusta | Arkansas | 2,051 |
| Judson | South Carolina | 2,050 |
All places in United States → · Nevada →
Figures are the latest available in GeoNames (CC BY 4.0), which draws on national censuses of varying dates — treat them as recent, not same-year. Country totals are UN World Population Prospects 2024 (medium variant) where the UN lists the country separately; the handful it reports under a parent state keep a GeoNames figure and are marked as such. Sources & method.