New York · United States
Lindenhurst population
27,277people · latest figure
Lindenhurst has a population of 27,277, making it the 1649th largest place we list in United States. It is in New York.
Lindenhurst holds under a tenth of one per cent of United States's 349,035,494 people. New York City, the largest place we list there, is 323 times its size. Twenty years earlier the World Gazetteer recorded 29,081, a fall of 6%.
The 2005 figure comes from the World Gazetteer archive restored on this site. The two sources may draw the settlement's boundary differently, so treat the change as indicative rather than exact. Why figures differ.
Lindenhurst is in New York, which has 1,109 recorded places.
Nearby in size
| Place | Region | Population |
|---|---|---|
| Anderson | South Carolina | 27,335 |
| Eagle Mountain | Utah | 27,332 |
| Winchester | Virginia | 27,284 |
| Spanaway | Washington | 27,227 |
| Holbrook | New York | 27,195 |
| New London | Connecticut | 27,179 |
All places in United States → · New York →
Figures are the latest available in GeoNames (CC BY 4.0), which draws on national censuses of varying dates — treat them as recent, not same-year. Country totals are UN World Population Prospects 2024 (medium variant) where the UN lists the country separately; the handful it reports under a parent state keep a GeoNames figure and are marked as such. Sources & method.