Tennessee · United States
Seymour population
10,919people · latest figure
Seymour has a population of 10,919, making it the 3638th largest place we list in United States. It is in Tennessee.
Seymour holds under a tenth of one per cent of United States's 349,035,494 people. New York City, the largest place we list there, is 806 times its size. Twenty years earlier the World Gazetteer recorded 18,730, a fall of 42%.
The 2005 figure comes from the World Gazetteer archive restored on this site. The two sources may draw the settlement's boundary differently, so treat the change as indicative rather than exact. Why figures differ.
Seymour is in Tennessee, which has 369 recorded places.
Nearby in size
| Place | Region | Population |
|---|---|---|
| Bluffdale | Utah | 10,931 |
| Malvern | Arkansas | 10,928 |
| Natrona Heights | Pennsylvania | 10,927 |
| Storm Lake | Iowa | 10,910 |
| Fairfield | Alabama | 10,907 |
| Ironton | Ohio | 10,900 |
All places in United States → · Tennessee →
Figures are the latest available in GeoNames (CC BY 4.0), which draws on national censuses of varying dates — treat them as recent, not same-year. Country totals are UN World Population Prospects 2024 (medium variant) where the UN lists the country separately; the handful it reports under a parent state keep a GeoNames figure and are marked as such. Sources & method.