Texas · United States
Seagoville population
15,894people · latest figure
Seagoville has a population of 15,894, making it the 2735th largest place we list in United States. It is in Texas.
Seagoville holds under a tenth of one per cent of United States's 349,035,494 people. New York City, the largest place we list there, is 554 times its size. Twenty years earlier the World Gazetteer recorded 11,007, a rise of 44%.
The 2005 figure comes from the World Gazetteer archive restored on this site. The two sources may draw the settlement's boundary differently, so treat the change as indicative rather than exact. Why figures differ.
Seagoville is in Texas, which has 1,247 recorded places.
Nearby in size
| Place | Region | Population |
|---|---|---|
| Parole | Maryland | 15,922 |
| La Marque | Texas | 15,908 |
| North Arlington | New Jersey | 15,904 |
| Lebanon | Indiana | 15,892 |
| Clayton | Missouri | 15,884 |
| Pearl River | New York | 15,876 |
All places in United States → · Texas →
Figures are the latest available in GeoNames (CC BY 4.0), which draws on national censuses of varying dates — treat them as recent, not same-year. Country totals are UN World Population Prospects 2024 (medium variant) where the UN lists the country separately; the handful it reports under a parent state keep a GeoNames figure and are marked as such. Sources & method.